Question 436: Waves Optics

Question

The distance of moon form the earth is $$3.8 	imes 10^5 \mathrm{~km}$$. Supposing that the eye is most sensitive to the light of wavelength $$550 \mathrm{~nm}$$, the separation of two points on the moon that can be resolved by a $$500 \mathrm{~cm}$$ telescope is

Accepted Answer

Resolving power $$=\frac{D}{1.22 \lambda}$$
$$\begin{aligned}
	ext { Given, } D & =3.8 	imes 10^5 \mathrm{~km}=3.8 	imes 10^8 \mathrm{~m} \
\lambda & =550 \mathrm{~nm}=550 	imes 10^9 \mathrm{~m} \
\Rightarrow \quad R P & =\frac{3.8 	imes 10^8}{1.22 	imes 550 	imes 10^9} \approx 55 \mathrm{~m} .
\end{aligned}$$

Answer

50 m

Answer

55 m

Answer

51 m

Answer

60 m

Waves Optics

The distance of moon form the earth is $3.8 \times 10^5 \mathrm{~km}. Supposing that the eye is most sensitive to the light of wavelength 550 \mathrm{~nm}, the separation of two points on the moon that can be resolved by a 500 \mathrm{~cm}$ telescope is

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