Question 109: Waves Optics

Question

Given below are two statements :
Statement I : If the Brewster's angle for the light propagating from air to glass is $$\mathrm{	heta_B}$$, then the Brewster's angle for the light propagating from glass to air is $$\frac{\pi}{2}-	heta_B$$
Statement II : The Brewster's angle for the light propagating from glass to air is $${	an ^{ - 1}}({\mu _\mathrm{g}})$$ where $$\mathrm{\mu_g}$$ is the refractive index of glass.
In the light of the above statements, choose the correct answer from the options given below :

Accepted Answer

Case I :
Transmitted is $\perp$ to reflected.
$i+r=90^{\circ}$
Snell's law
$\mu_{a} \sin i=\mu_{g} \sin r$
$	an i=\frac{\mu_{g}}{\mu_{a}}$
$i=	an ^{-1}\left(\frac{\mu_{g}}{\mu_{a}}ight)=	heta_{B}$
Case II :
$i+r=90^{\circ}$ as transmitted is $\perp$ to reflected.
$	an i=\frac{\mu_{a}}{\mu_{g}} \Rightarrow i=	an ^{-1} \frac{\mu_{a}}{\mu_{g}}=\frac{\pi}{2}-	heta_{B}$

Answer

Both Statement I and Statement II are false

Answer

Both Statement I and Statement II are true

Answer

Statement I is false but Statement II is true

Answer

Statement I is true but Statement II is false

Waves Optics

Choose the correct answer: