Question 181: Ray Optics

Question

A prism of refractive index $$\mu$$ and angle of prism A is placed in the position of minimum angle of deviation. If minimum angle of deviation is also A, then in terms of refractive index

Accepted Answer

$$\mu  = {{\sin \left( {{{A + {\delta _{\min }}} \over 2}} \right)} \over {\sin \left( {{A \over 2}} \right)}}$$
$$\mu  = {{\sin \left( {{{A + A} \over 2}} \right)} \over {\sin \left( {{A \over 2}} \right)}}$$
$$\mu  = {{\sin A} \over {\sin {A \over 2}}} = 2\cos {A \over 2}$$
$$A = 2{\cos ^{ - 1}}\left( {{\mu  \over 2}} \right)$$

Answer

$$2{\cos ^{ - 1}}\left( {{\mu  \over 2}} \right)$$

Answer

$${\sin ^{ - 1}}\left( {{\mu  \over 2}} \right)$$

Answer

$${\sin ^{ - 1}}\left( {\sqrt {{{\mu  - 1} \over 2}} } \right)$$

Answer

$${\cos ^{ - 1}}\left( {{\mu  \over 2}} \right)$$

Ray Optics

A prism of refractive index $\mu$ and angle of prism A is placed in the position of minimum angle of deviation. If minimum angle of deviation is also A, then in terms of refractive index

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