Question 166: Ray Optics

Question

The speed of light in media 'A' and 'B' are $$2.0 	imes {10^{10}}$$ cm/s and $$1.5 	imes {10^{10}}$$ cm/s respectively. A ray of light enters from the medium B to A at an incident angle '$$	heta$$'. If the ray suffers total internal reflection, then

Accepted Answer

$${\mu _A} = {{3 	imes {{10}^8}} \over {2 	imes {{10}^8}}} = 1.5$$
$${\mu _B} = {{3 	imes {{10}^8}} \over {1.5 	imes {{10}^8}}} = 2$$
For TIR
$$	heta  > {i_c}$$
$$	heta  > {\sin ^{ - 1}}\left( {{{1.5} \over 2}} ight)$$
$$	heta  > {\sin ^{ - 1}}\left( {{3 \over 4}} ight)$$

Answer

$$	heta  = {\sin ^{ - 1}}\left( {{3 \over 4}} ight)$$

Answer

$$	heta  > {\sin ^{ - 1}}\left( {{2 \over 3}} ight)$$

Answer

$$	heta  < {\sin ^{ - 1}}\left( {{3 \over 4}} ight)$$

Answer

$$	heta  > {\sin ^{ - 1}}\left( {{3 \over 4}} ight)$$

Ray Optics

The speed of light in media 'A' and 'B' are $2.0 \times {10^{10}} cm/s and 1.5 \times {10^{10}} cm/s respectively. A ray of light enters from the medium B to A at an incident angle '\theta$'. If the ray suffers total internal reflection, then

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