Question 290: Ray Optics

Question

As shown in the figure, a plane mirror is fixed at a height of $$50 \mathrm{~cm}$$ from the bottom of tank containing water $$\left(\mu=\frac{4}{3}\right)$$. The height of water in the tank is $$8 \mathrm{~cm}$$. A small bulb is placed at the bottom of the water tank. The distance of image of the bulb formed by mirror from the bottom of the tank is ___________ $$\mathrm{cm}$$.

Accepted Answer

$$
	ext { Apparent depth of } \mathrm{O}=\frac{\mathrm{d}}{\mu}
$$$$
=\frac{8}{\frac{4}{3}}=6 \mathrm{~cm}
$$
Distance of object from mirror = 42 + 6 = 48 m
$$
	ext { Distance between } \mathrm{O} 	ext { and } \mathrm{I}_2=48+50=98 \mathrm{~cm}
$$

Ray Optics

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