Question 192: EM waves

Question

In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of $$2.0 	imes 10^{10} \mathrm{~Hz}$$ and amplitude $$48 ~\mathrm{Vm}^{-1}$$. Then the amplitude of oscillating magnetic field is : (Speed of light in free space $$=3 	imes 10^{8} \mathrm{~m} \mathrm{~s}^{-1}$$ )

Accepted Answer

$$C=\frac{E_{0}}{B_{0}}$$
$$\mathrm{B}_{0}=\frac{\mathrm{E}_{0}}{\mathrm{C}}$$
$$=\frac{48}{3 	imes 10^{8}}$$
$$=1.6 	imes 10^{-7} \mathrm{~T}$$

Answer

$$1.6 	imes 10^{-8} \mathrm{~T}$$

Answer

$$1.6 	imes 10^{-7} \mathrm{~T}$$

Answer

$$1.6 	imes 10^{-6} \mathrm{~T}$$

Answer

$$1.6 	imes 10^{-9} \mathrm{~T}$$

EM waves

Choose the correct answer: