Question 56: EM waves

Question

The electric field of an electromagnetic wave in free space is represented as $$\overrightarrow{\mathrm{E}}=\mathrm{E}_0 \cos (\omega \mathrm{t}-\mathrm{kz}) \hat{i}$$. The corresponding magnetic induction vector will be :

Accepted Answer

$$\begin{aligned}
& 	ext { Given } \vec{E}=E_0 \cos (\omega t-k z) \hat{i} \
& \vec{B}=\frac{E_0}{C} \cos (\omega t-k z) \hat{j} \
& \hat{C}=\hat{E} 	imes \hat{B}
\end{aligned}$$

Answer

$$\overrightarrow{\mathrm{B}}=\mathrm{E}_0 \mathrm{C} \cos (\omega \mathrm{t}+\mathrm{k} z) \hat{j}$$

Answer

$$\overrightarrow{\mathrm{B}}=\frac{\mathrm{E}_0}{\mathrm{C}} \cos (\omega \mathrm{t}-\mathrm{kz}) \hat{j}$$

Answer

$$\overrightarrow{\mathrm{B}}=\mathrm{E}_0 \mathrm{C} \cos (\omega \mathrm{t}-\mathrm{k} z) \hat{j}$$

Answer

$$\overrightarrow{\mathrm{B}}=\frac{\mathrm{E}_0}{\mathrm{C}} \cos (\omega \mathrm{t}+\mathrm{kz}) \hat{j}$$

EM waves

The electric field of an electromagnetic wave in free space is represented as $\overrightarrow{\mathrm{E}}=\mathrm{E}_0 \cos (\omega \mathrm{t}-\mathrm{kz}) \hat{i}$. The corresponding magnetic induction vector will be :

Choose the correct answer: