Question 137: EM waves

Question

A light wave is incident normally on a glass slab of refractive index 1.5. If 4 % of light gets reflected and the amplitude of the electric field of the incident light is 30 V/m, then the amplitude of the electric field for the wave propagating in the glass medium will be :

Accepted Answer

P
refracted
= $${{96} \over {100}}Pi$$
$$ \Rightarrow $$  K
2
A$$Pi_t^2$$ = $${{96} \over {100}}$$ K
1
A$$_i^2$$
$$ \Rightarrow $$  r
2
A$$_i^2$$ = $${{96} \over {100}}$$ r
1
A$$_i^2$$
$$ \Rightarrow $$  A$$_t^2$$ = $${{96} \over {100}} 	imes {1 \over {{3 \over 2}}} 	imes {\left( {30} ight)^2}$$
A
1
$$\sqrt {{{64} \over {100}} 	imes {{\left( {30} ight)}^2}}  = 24$$

Answer

6 V/m

Answer

10 V/m

Answer

30 V/m

Answer

24 V/m

EM waves

A light wave is incident normally on a glass slab of refractive index 1.5. If 4 % of light gets reflected and the amplitude of the electric field of the incident light is 30 V/m, then the amplitude of the electric field for the wave propagating in the glass medium will be :

Choose the correct answer: