Question 188: EM waves

Question

The electric field in a plane electromagnetic wave is given by $$
E_z=60 \cos \left(5 x+1.5 	imes 10^9 tight) \mathrm{V} / \mathrm{m}$$ Then expression for the corresponding magnetic field is (here subscripts denote the direction of the field) :

Accepted Answer

In electromagnetic wave, $E$ and $B$ are in same phase and $B_0=\frac{E_0}{c}$; their planes are perpendicular to each other.
$$\begin{aligned}
& 	herefore B_y=\frac{60}{c} \cos \left(5 x+1.5 	imes 10^9 tight) \mathrm{T} \
& =\frac{60}{3 	imes 10^8} \cos \left(5 x+1.5 	imes 10^9 tight) \mathrm{T} \
& B_y=2 	imes 10^{-7} \cos \left(5 x+1.5 	imes 10^9 tight) \mathrm{T}
\end{aligned}$$

Answer

$B z=60 \cos \left(5 x+1.5 	imes 10^9 tight) T$

Answer

$B_y=60 \sin \left(5 x+1.5 	imes 10^9 tight) T$

Answer

$B_y=2 	imes 10^{-7} \cos \left(5 x+1.5 	imes 10^9 tight) T$

Answer

$B_x=2 	imes 10^{-7} \cos \left(5 x+1.5 	imes 10^9 tight) T$

EM waves

The electric field in a plane electromagnetic wave is given by $ E_z=60 \cos \left(5 x+1.5 \times 10^9 t\right) \mathrm{V} / \mathrm{m}$ Then expression for the corresponding magnetic field is (here subscripts denote the direction of the field) :

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