Question 333: AC fundamentals

Question

An alternating current is given by $\mathrm{I}=100 \sin (50 \pi \mathrm{t})$. How many times will the current become zero in one second?

Accepted Answer

Current is given by, $\mathrm{I}=\mathrm{I}_0 \sin \omega \mathrm{t}\quad	ext{.... (i)}$
Given, $I=100 \sin (50 \pi \mathrm{t}$)
Comparing with (i),
$$\omega=50 \pi$$
$	herefore \quad 2 \pi \mathrm{f}=50 \pi$
$	herefore \quad \mathrm{f}=25 \mathrm{~Hz} \Rightarrow 25$ cycles per second Current becomes zero twice in one cycle
$	herefore \quad$ Current becomes zero, $25 	imes 2=50$ times

Answer

50 times

Answer

25 times

Answer

40 times

Answer

100 times

AC fundamentals

An alternating current is given by \mathrm{I}=100 \sin (50 \pi \mathrm{t}). How many times will the current become zero in one second?

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