Question 442: AC fundamentals

Question

In an ideal transformer, the turns ratio is $$\frac{N_P}{N_S}=\frac{1}{2}$$. The ratio $$V_S: V_P$$ is equal to (the symbols carry their usual meaning) :

Accepted Answer

An ideal transformer is a device that transfers electrical energy from one circuit to another through inductively coupled conductorsÃ¢ÂÂthe transformer's coils. The primary coil (with $$N_P$$ turns) is connected to the input voltage ($$V_P$$), and the secondary coil (with $$N_S$$ turns) delivers the output voltage ($$V_S$$).
The relationship between the input (primary) voltage and output (secondary) voltage in a transformer is determined by the ratio of the number of turns in the primary coil to the number of turns in the secondary coil, expressed by the formula:
$$
\frac{V_S}{V_P} = \frac{N_S}{N_P}
$$
In this case, the given turns ratio is $$\frac{N_P}{N_S} = \frac{1}{2}$$. To find the correct expression for $$\frac{V_S}{V_P}$$, we need to invert the given ratio to reflect the relationship with respect to the voltages. This means:
$$
\frac{N_S}{N_P} = 2
$$
Therefore, substituting into the voltage ratio equation:
$$
\frac{V_S}{V_P} = 2
$$
This indicates that the secondary voltage ($$V_S$$) is twice the primary voltage ($$V_P$$). If we were to express the ratio $$V_S:V_P$$ based on this, it would be:
Option B
$$2: 1$$
This is the correct answer as it represents that, in accordance with the transformer's turns ratio, the voltage in the secondary coil is twice that in the primary coil.

Answer

$$1: 2$$

Answer

$$2: 1$$

Answer

$$1: 1$$

Answer

$$1: 4$$

AC fundamentals

In an ideal transformer, the turns ratio is $\frac{N_P}{N_S}=\frac{1}{2}. The ratio V_S: V_P$ is equal to (the symbols carry their usual meaning) :

Choose the correct answer: