Question 426: AC fundamentals

Question

In an ideal step down transformer, out of the following quantities, which quantity increases in the secondary coil?

Accepted Answer

For an ideal transformer,
$$\frac{V_s}{V_p}=\frac{I_p}{I_s}$$
Hence, if $$V_s < V_p$$ then $$I_p < I_s$$

Answer

Power

Answer

Voltage

Answer

Current

Answer

Frequency

AC fundamentals