Question 236: AC fundamentals

Question

In an $$LCR$$ circuit as shown below both switches are open initially. Now switch $${S_1}$$ is closed, $${S_2}$$ kept open. ($$q$$ is charge on the capacitor and $$	au $$ $$=RC$$ is Capacitance time constant). Which of the following statement is correct ?

Accepted Answer

Charge on he capacitor at any time $$t$$ is given by
$$q = CV\left( {1 - {e^{t/	au }}} ight)$$
at $$t = 2	au $$
$$q = CV\left( {1 - {e^{ - 2}}} ight)$$

Answer

Work done by the battery is half of the energy dissipated in the resistor

Answer

$$t = \,	au ,\,q = CV/2$$

Answer

At $$t = \,2	au ,\,q = CV\left( {1 - {e^{ - 2}}} ight)$$

Answer

At $$t = \,2	au ,\,q = CV\left( {1 - {e^{ - 1}}} ight)$$

AC fundamentals

In an $LCR circuit as shown below both switches are open initially. Now switch {S_1} is closed, {S_2} kept open. (q is charge on the capacitor and \tau =RC$ is Capacitance time constant). Which of the following statement is correct ?

Choose the correct answer: