Question 400: AC fundamentals

Question

In the part of an a.c. circuit as shown, the resistance $$R=0.2 \Omega$$. At a certain instant $$(\mathrm{V_A-V_B})= 0.5 \mathrm{~V}, \mathrm{I}=0.5 \mathrm{~A}$$ and $$\frac{\Delta \mathrm{I}}{\Delta \mathrm{t}}=8 \mathrm{~A} / \mathrm{s}$$. The inductance of the coil is

Accepted Answer

In the part of an a.c. circuit
$$\begin{aligned}
& V_A-V_B=\mathrm{L} \frac{\mathrm{dI}}{\mathrm{dt}}+\mathrm{IR} \
& 0.5=8 \mathrm{~L}+0.5 	imes 0.2 \
& 	herefore 8 \mathrm{~L}=0.4 \
& 	herefore \quad \mathrm{L}=\frac{0.4}{8}=0.05 \mathrm{~H}
\end{aligned}$$

Answer

0.04 H

Answer

0.02 H

Answer

0.08 H

Answer

0.05 H

AC fundamentals

In the part of an a.c. circuit as shown, the resistance $R=0.2 \Omega. At a certain instant (\mathrm{V_A-V_B})= 0.5 \mathrm{~V}, \mathrm{I}=0.5 \mathrm{~A} and \frac{\Delta \mathrm{I}}{\Delta \mathrm{t}}=8 \mathrm{~A} / \mathrm{s}$. The inductance of the coil is

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