Question 159: AC fundamentals

Question

An alternating voltage source $\mathrm{V}=260 \sin (628 \mathrm{t}$ ) is connected across a pure inductor of $5 \mathrm{mH}$ Inductive reactance in the circuit is :

Accepted Answer

$\omega$ = 628 rad/s
$X_{L}=L \omega$
$$
\begin{aligned}
& =5 \mathrm{mH} 	imes 628 \\
& =3.14 \Omega
\end{aligned}
$$

Answer

$6.28 \Omega$

Answer

$0.318 \Omega$

Answer

$0.5 \Omega$

Answer

$3.14 \Omega$

AC fundamentals

An alternating voltage source \mathrm{V}=260 \sin (628 \mathrm{t} ) is connected across a pure inductor of 5 \mathrm{mH} Inductive reactance in the circuit is :

Choose the correct answer: