Question 440: AC fundamentals

Question

A step up transformer is connected to an ac mains supply of $$220 \mathrm{~V}$$ to operate at $$11000 \mathrm{~V}, 88$$ watt. The current in the secondary circuit, ignoring the power loss in the transformer, is

Accepted Answer

Let's analyze the problem step by step. We are given a step-up transformer with the following specifications:
Primary Voltage (V
p
)
= $$220 \mathrm{~V}$$
Secondary Voltage (V
s
)
= $$11000 \mathrm{~V}$$
Power (P)
= $$88$$ watt
The power input to the transformer is equal to the power output, assuming there is no loss in the transformer.
Hence,
$$P_{primary} = P_{secondary} = P = 88 \mathrm{~W}$$
The power equations can be written as:
$$P_{primary} = V_p I_p$$
$$P_{secondary} = V_s I_s$$
Given the power in the secondary winding is $$88 \mathrm{~W}$$ and the secondary voltage is $$11000 \mathrm{~V}$$, we can find the secondary current $$I_s$$ using the formula:
$$P_{secondary} = V_s I_s$$
Rearranging to solve for $$I_s$$ gives:
$$I_s = \frac{P}{V_s}$$
Substituting the given values:
$$I_s = \frac{88 \mathrm{~W}}{11000 \mathrm{~V}}$$
Simplifying this expression:
$$I_s = \frac{88}{11000} \mathrm{~A}$$
$$I_s = 0.008 \mathrm{~A}$$
$$I_s = 8 \mathrm{~mA}$$
Therefore, the current in the secondary circuit, ignoring the power loss in the transformer, is
8 mA
.
The correct option is
Option A: 8 mA
.

Answer

8 mA

Answer

4 mA

Answer

0.4 A

Answer

4 A

AC fundamentals

A step up transformer is connected to an ac mains supply of $220 \mathrm{~V} to operate at 11000 \mathrm{~V}, 88$ watt. The current in the secondary circuit, ignoring the power loss in the transformer, is

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