Question 357: AC fundamentals

Question

A coil having an inductance of $$\frac{1}{\pi} \mathrm{H}$$ is connected in series with a resistance of $$300 \Omega$$. If $$20 \mathrm{~V}$$ from a $$200 \mathrm{~Hz}$$ source are impressed across the combination, the value of the phase angle between the voltage and the current is

Accepted Answer

$$\begin{aligned}
& \mathrm{X}_{\mathrm{L}}=\mathrm{L} \omega=\mathrm{L} 	imes 2 \pi \mathrm{f} \
	herefore \quad \mathrm{X}_{\mathrm{L}} & =\frac{1}{\pi} 	imes 2 \pi 	imes 200 \
	herefore \quad \mathrm{X}_{\mathrm{L}} & =400 \Omega
\end{aligned}$$
Now, the phase angle between voltage and current is given by, $$	an \phi=\frac{X_L}{R}=\frac{400}{300}$$
$$	herefore \quad \phi=	an ^{-1}\left(\frac{4}{3}ight)$$

Answer

$$	an ^{-1}\left(\frac{5}{4}ight)$$

Answer

$$	an _{-1}\left(\frac{4}{5}ight)$$

Answer

$$	an ^{-1}\left(\frac{3}{4}ight)$$

Answer

$$	an ^{-1}\left(\frac{4}{3}ight)$$

AC fundamentals

A coil having an inductance of $\frac{1}{\pi} \mathrm{H} is connected in series with a resistance of 300 \Omega. If 20 \mathrm{~V} from a 200 \mathrm{~Hz}$ source are impressed across the combination, the value of the phase angle between the voltage and the current is

Choose the correct answer: