Question 500: AC fundamentals

Question

A transformer has 200 windings in the primary and 400 windings in the secondary. The primary is connected to an AC supply of 110 V and a current of 10 A flows in it. The voltage across the secondary and the current in it, respectively, are

Accepted Answer

In an ideal transformer, the voltage and current ratios are given by:
$$\frac{V_s}{V_p} = \frac{N_s}{N_p}$$
$$\frac{I_p}{I_s} = \frac{N_s}{N_p}$$
Given:
Primary windings, $$N_p = 200$$
Secondary windings, $$N_s = 400$$
Primary voltage, $$V_p = 110 	ext{ V}$$
Primary current, $$I_p = 10 	ext{ A}$$
Step-by-step solution:
Calculate the turns ratio:
$$\frac{N_s}{N_p} = \frac{400}{200} = 2$$
Determine the secondary voltage:
$$V_s = \frac{N_s}{N_p} \cdot V_p = 2 	imes 110 	ext{ V} = 220 	ext{ V}$$
Determine the secondary current:
$$\frac{I_p}{I_s} = \frac{N_s}{N_p} \quad \Rightarrow \quad I_s = \frac{I_p}{2} = \frac{10 	ext{ A}}{2} = 5 	ext{ A}$$
Thus, the voltage across the secondary is $$220 	ext{ V}$$ and the current in it is $$5 	ext{ A}$$.
The correct answer is Option D: $$220 \mathrm{~V}, 5 \mathrm{~A}.$$

Answer

$55 \mathrm{~V}, 20 \mathrm{~A}$

Answer

$440 \mathrm{~V}, 5 \mathrm{~A}$

Answer

$220 \mathrm{~V}, 10 \mathrm{~A}$

Answer

$220 \mathrm{~V}, 5 \mathrm{~A}$

AC fundamentals

A transformer has 200 windings in the primary and 400 windings in the secondary. The primary is connected to an AC supply of 110 V and a current of 10 A flows in it. The voltage across the secondary and the current in it, respectively, are

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