Question 231: Electromagnetic Induction

Question

The self-inductance of a circuit is numerically equal to

Accepted Answer

Self-inductance ($L$) of a circuit is defined as the ratio of the magnetic flux linked with the circuit to the current producing it:
$$ L = \frac{\Phi}{I} $$
The work done ($W$) in establishing a current $I$ against the induced emf is given by:
$$ W = \frac{1}{2} L I^2 $$
Now, if the current is unity ($I = 1$):
$$ W = \frac{1}{2} L (1)^2 = \frac{1}{2} L $$
Therefore,
$$ L = 2 	imes 	ext{(work done in establishing unit current)} $$
Thus, the correct answer is:
Option B
twice the work done in establishing the magnetic flux associated with unit current in the circuit.

Answer

the work done in establishing the magnetic flux associated with circuit.

Answer

twice the work done in establishing the magnetic flux associated with unit current in the circuit.

Answer

thrice the work done in establishing the magnetic flux associated with unit current in the circuit.

Answer

the work done in establishing the magnetic flux associated with unit current in the circuit.

Electromagnetic Induction

The self-inductance of a circuit is numerically equal to

Choose the correct answer: