Question 122: Electromagnetic Induction

Question

A conducting circular loop made of a thin wire, has area 3.5 $$ 	imes $$ 10$$-$$3 m2 and resistance 10 $$\Omega $$. It is placed perpendicular to a time dependent magnetic field B(t) = (0.4T)sin(50$$\pi $$t). The field is uniform in space. Then the net charge flowing through the loop during t = 0 s and t = 10 ms is close to :

Accepted Answer

At    t  =  0 s
B(0)   =  0.4 sin (0) =  0
and at t  =  10 ms
B(10)  =  0.4 sin (50$$\pi $$$$ 	imes $$10$$ 	imes $$10
-3
)
=  0.4  sin $$\left( {{\pi  \over 2}} ight)$$
=  0.4
As   q  =  $${{\Delta \phi } \over R}$$
=  $${{A\left[ {B\left( {10} ight) - B\left( 0 ight)} ight]} \over {10}}$$
=  $${{3.5 	imes {{10}^{ - 3}}\left[ {0.4 - 0} ight]} \over {10}}$$
=  0.14 mC

Answer

0.14 mC

Answer

0.7 mC

Answer

0.21 mC

Answer

0.6 mC

Electromagnetic Induction

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