Question 3: Electromagnetic Induction

Question

A circular loop of radius 0.3 cm lies parallel
to a much bigger circular loop of radius 20 cm.
The centre of the small loop on the axis of
the bigger loop. The distance between their
centres is 15 cm. If a current of 20 A flows
through the smaller loop, then the flux
linked with bigger drop is

Accepted Answer

Magnetic flux linked with bigger circular loop
is given by
$$\phi=\frac{\mu_0}{2} \cdot \frac{\pi I R_1^2 R_2^2}{\left(R_1^2+x^2ight)^{3 / 2}}$$
Putting the values,
$$\phi=\frac{4 \pi 	imes 10^{-7} 	imes \pi 	imes 15 	imes\left(0.3 	imes 10^{-2}ight)^2 	imes\left(20 	imes 10^{-2}ight)^2}{\left[\left(0.3 	imes 10^{-2}ight)^2+\left(15 	imes 10^{-2}ight)^2ight]^{3 / 2}}$$
By solving, we get
$$\phi=9.116 	imes 10^{-11} \mathrm{~Wb}$$

Answer

$$9.1 	imes 10^{-11} \mathrm{~Wb}$$

Answer

$$6 	imes 10^{-11} \mathrm{~Wb}$$

Answer

$$3.3 	imes 10^{-11} \mathrm{~Wb}$$

Answer

$$6.6 	imes 10^{-9} \mathrm{~Wb}$$

Electromagnetic Induction

A circular loop of radius 0.3 cm lies parallel to a much bigger circular loop of radius 20 cm. The centre of the small loop on the axis of the bigger loop. The distance between their centres is 15 cm. If a current of 20 A flows through the smaller loop, then the flux linked with bigger drop is

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