Question 64: Magnetism and Matter

Question

Two particles $$X$$ and $$Y$$ having equal charges are being accelerated through the same potential difference. Thereafter they enter normally in a region of uniform magnetic field and describes circular paths of radii $$R_1$$ and $$R_2$$ respectively. The mass ratio of $$X$$ and $$Y$$ is :

Accepted Answer

$$\begin{aligned}
& \mathrm{R}=\frac{\mathrm{mv}}{\mathrm{qB}}=\frac{\mathrm{p}}{\mathrm{qB}}=\frac{\sqrt{2 \mathrm{~m}(\mathrm{KE})}}{\mathrm{qB}}=\frac{\sqrt{2 \mathrm{mqV}}}{\mathrm{qB}} \
& \mathrm{R} \propto \sqrt{\mathrm{m}} \
& \mathrm{m} \propto \mathrm{R}^2 \
& \frac{\mathrm{m}_1}{\mathrm{~m}_2}=\left(\frac{\mathrm{R}_1}{\mathrm{R}_2}ight)^2
\end{aligned}$$

Answer

$$\left(\frac{R_1}{R_2}\right)$$

Answer

$$\left(\frac{R_2}{R_1}\right)$$

Answer

$$\left(\frac{R_2}{R_1}\right)^2$$

Answer

$$\left(\frac{R_1}{R_2}\right)^2$$

Magnetism and Matter

Two particles $X and Y having equal charges are being accelerated through the same potential difference. Thereafter they enter normally in a region of uniform magnetic field and describes circular paths of radii R_1 and R_2 respectively. The mass ratio of X and Y$ is :

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