Question 150: Magnetism and Matter

Question

A proton, a deutron and an $$\alpha$$-particle with same kinetic energy enter into a uniform magnetic field at right angle to magnetic field. The ratio of the radii of their respective circular paths is :

Accepted Answer

$$	herefore$$ $$r = {{mv} \over {qB}} = {{\sqrt {2m(KE)} } \over {qB}}$$
$$ \Rightarrow {r_1}:{r_2}:{r_3} = {{\sqrt {{m_1}} } \over {{q_1}}}:{{\sqrt {{m_2}} } \over {{q_2}}}:{{\sqrt {{m_3}} } \over {{q_3}}}$$
$$ = {{\sqrt 1 } \over 1}:{{\sqrt 2 } \over 1}:{{\sqrt 4 } \over 2}$$
$$ = 1:\sqrt 2 :1$$

Answer

1 : $$\sqrt 2 $$ : $$\sqrt 2 $$

Answer

1 : 1 : $$\sqrt 2 $$

Answer

$$\sqrt 2 $$ : 1 : 1

Answer

1 : $$\sqrt 2 $$ : 1

Magnetism and Matter

A proton, a deutron and an $\alpha$-particle with same kinetic energy enter into a uniform magnetic field at right angle to magnetic field. The ratio of the radii of their respective circular paths is :

Choose the correct answer: