Question 172: Magnetism and Matter

Question

A particle of charge q and mass m is moving with a velocity $$ - v\widehat i$$ (v $$ 
e $$ 0) towards a large screen
placed in the Y - Z plane at a distance d. If there is a magnetic field $$\overrightarrow B  = {B_0}\widehat k$$
, the maximum value of v
for which the particle will not hit the screen is :

Accepted Answer

In uniform magnetic field particle moves in a circular path, if the radius of the circular path is 'd', particle will
not hit the screen.
r = $${{mv} \over {q{B_0}}}$$
To not collide, r < d
$$ \Rightarrow $$ $${{mv} \over {q{B_0}}}$$ < d
$$ \Rightarrow $$ v < $${{q{B_0}d} \over m}$$
$$ 	herefore $$ v
max
= $${{q{B_0}d} \over m}$$

Answer

$${{2qd{B_0}} \over m}$$

Answer

$${{qd{B_0}} \over {3m}}$$

Answer

$${{qd{B_0}} \over {2m}}$$

Answer

$${{qd{B_0}} \over {m}}$$

Magnetism and Matter

A particle of charge q and mass m is moving with a velocity $ - v\widehat i (v \ne 0) towards a large screen placed in the Y - Z plane at a distance d. If there is a magnetic field \overrightarrow B = {B_0}\widehat k$ , the maximum value of v for which the particle will not hit the screen is :

Choose the correct answer: