Question 245: Current Electricity

Question

Five equal resistances are connected in a network as shown in figure. The net resistance between the points A and B is :

Accepted Answer

Given all resistances have same resistance R.
Now, we can redraw the circuit as below
Let resistances be R
1
, R
2
, R
3
and R
4
.
$$\because$$ $${{{R_1}} \over {{R_3}}} = {{{R_2}} \over {{R_4}}}$$
So, circuit will behave as a Wheatstone bridge and no current will flow through middle resistor.
$$	herefore$$ $${R_{eq}} = {{({R_1} + {R_2})({R_3} + {R_4})} \over {({R_1} + {R_2}) + ({R_3} + {R_4})}}$$
$$ = {{(R + R)(R + R)} \over {(R + R) + (R + R)}}$$
$$ = R$$

Answer

$${{3R} \over 2}$$

Answer

$${{R} \over 2}$$

Answer

2R

Answer

R

Current Electricity

Five equal resistances are connected in a network as shown in figure. The net resistance between the points A and B is :

Choose the correct answer: