Question 553: Current Electricity

Question

Only $$4 \%$$ of the total current in the circuit passes through a galvanometer. If the resistance of the galvanometer is $$G$$, then the shunt resistance connected to the galvanometer is

Accepted Answer

From the given figure, we have $$\left(I-I_Gight) S=I_G G$$
Image
$$\Rightarrow \quad S=\frac{I_G G}{\left(I-I_Gight)}$$
$$	ext { Here, } I_G=\frac{4 I}{100}=\frac{I}{25}$$
$$\begin{aligned}
	herefore \quad S & =\frac{\frac{1}{25} 	imes G}{I-\frac{1}{25}} \
& =\frac{\frac{G}{25}}{\frac{24}{25}}=\frac{1}{24} 	imes G \
& =\frac{G}{24}
\end{aligned}$$

Answer

$$\frac{G}{25}$$

Answer

$$\frac{G}{24}$$

Answer

24G

Answer

25G

Current Electricity

Only $4 \% of the total current in the circuit passes through a galvanometer. If the resistance of the galvanometer is G$, then the shunt resistance connected to the galvanometer is

Choose the correct answer: