Question 576: Current Electricity

Question

In a potentiometer experiement, when three cells $$\mathrm{A}, \mathrm{B}$$ and $$\mathrm{C}$$ are connected in series, the balancing length is found to be $$420 \mathrm{~cm}$$. If cells $$\mathrm{A}$$ and $$\mathrm{B}$$ are connected in series the balancing length is $$220 \mathrm{~cm}$$ and for cells $$\mathrm{B}$$ and $$\mathrm{C}$$ connected in series in balancing length is $$320 \mathrm{~cm}$$. The emf of cells $$\mathrm{A}, \mathrm{B}$$ and $$\mathrm{C}$$ are respectively in the ratio of

Accepted Answer

$$\begin{aligned}
& B+C=420 \
& A+B=220 \mathrm{~cm} \quad 	herefore C=420-220=200 \mathrm{~cm} \
& B+C=320 \mathrm{~cm} \quad 	herefore B=320-200=120 \mathrm{~cm} \
& A=220-B=100 \mathrm{~cm} \
& 	herefore A: B: C:: 1: 1.2: 2
\end{aligned}$$

Answer

$$2: 3: 5$$

Answer

$$5: 4: 3$$

Answer

$$1: 1.2: 2$$

Answer

$$1.2: 1: 2$$

Current Electricity

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