Question 606: Current Electricity

Question

The range of an ammeter of resistance ' $G$ can be increased from ' $I$ ' to ' $nI$ ' by connecting

Accepted Answer

The range of an ammeter can be increased by connecting a shunt or parallel resistance to it, whose value is given by
$$R=\left(\frac{I_g}{I-I_g}ight) G \Omega\quad	ext{.... (i)}$$
To increase the range from / to nl , the current passing through it is $I=n I_g$
Using this value in Eq. (i), we get
$$\begin{aligned}
R & =\left(\frac{I_g}{n I_g-I_g}ight) G \
& =\frac{G}{(n-1)} \Omega
\end{aligned}$$

Answer

a series resistance of $\frac{G}{n+1} \Omega$

Answer

a shunt of $\frac{G}{n-1} \Omega$

Answer

a shunt of $\frac{G}{n+1} \Omega$

Answer

a series resistance of $\frac{G}{n-1} \Omega$

Current Electricity

The range of an ammeter of resistance ' G can be increased from ' I ' to ' nI ' by connecting

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