Question 2: Current Electricity

Question

For a wire $$\frac{R}{\ell}=\frac{1}{2}$$ and length of wire is $$\ell=5 \mathrm{~cm}$$. If potential difference of $$\mathrm{l} \mathrm{V}$$ is applied across it, then current through wire will be ($$R=$$ Resistance)

Accepted Answer

Given, for a wire, $$\frac{R}{l}=\frac{1}{2}$$
Length of wire, $$l=5 \mathrm{~cm}=5 	imes 10^{-2} \mathrm{~m}$$
$$	herefore \quad R=\frac{l}{2}=2.5 	imes 10^{-2} \Omega$$
Potential difference, $$V=1 \mathrm{~V}$$ or $$I R=1$$
$$I=\frac{1}{R}=\frac{1}{2.5 	imes 10^{-2}}=\frac{100}{2.5}=40 \mathrm{~A}$$

Answer

40 A

Answer

4 A

Answer

25 A

Answer

2.5 A

Current Electricity

For a wire $\frac{R}{\ell}=\frac{1}{2} and length of wire is \ell=5 \mathrm{~cm}. If potential difference of \mathrm{l} \mathrm{V} is applied across it, then current through wire will be (R=$ Resistance)

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