Question 256: Current Electricity

Question

Two resistors 400$$\Omega $$  and 800$$\Omega $$ are connected in series across a 6 V battery. The potential difference measured by a voltmeter of 10 k$$\Omega $$ across 400 $$\Omega $$ resistor is close to :

Accepted Answer

$$i = {6 \over {800 + {{400 	imes 10000} \over {400 + 10000}}}}$$
$$i = {6 \over {800 + {{40000} \over {104}}}}$$
$$i = {6 \over {800 + 384.61}} = {6 \over {1184.61}} = 0.00506$$
V
400
= i
1
$$ 	imes $$ 400
= $$\left( {{{{{10}^4}} \over {400 + {{10}^4}}}} ight)i 	imes 400$$
= $$\left( {{{{{10}^4}} \over {400 + {{10}^4}}}} ight)\left( {0.00506} ight) 	imes 400$$
= 1.95 V

Answer

2.05 V

Answer

1.95 V

Answer

2 V

Answer

1.8 V

Current Electricity

Two resistors 400$\Omega and 800\Omega are connected in series across a 6 V battery. The potential difference measured by a voltmeter of 10 k\Omega across 400 \Omega $ resistor is close to :

Choose the correct answer: