Question 630: Current Electricity

Question

10 resistors, each of resistance $$\mathrm{R}$$ are connected in series to a battery of emf $$E$$ and negligible internal resistance. Then those are connected in parallel to the same battery, the current is increased $$n$$ times. The value of $$n$$ is :

Accepted Answer

$$\mathrm{I}_{\mathrm{S}}=\frac{E}{10 R}$$ ..... (1)
$$\mathrm{I}_{\mathrm{P}}=\frac{\mathrm{E}}{\mathrm{R} / 10}=\frac{10 \mathrm{E}}{\mathrm{R}}$$ .... (2)
$$\mathrm{n}=\frac{\mathrm{I}_{\mathrm{P}}}{\mathrm{I}_{\mathrm{S}}}=100 \Rightarrow \mathrm{n}=100$$

Answer

100

Answer

1

Answer

1000

Answer

10

Current Electricity

10 resistors, each of resistance $\mathrm{R} are connected in series to a battery of emf E and negligible internal resistance. Then those are connected in parallel to the same battery, the current is increased n times. The value of n$ is :

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