Question 540: Current Electricity

Question

In the following circuit, a power of 50 watt is absorbed in the section AB of the circuit. The value of resistance ' $x$ ' is

Accepted Answer

Kirchhoff's Current Law (KCL)
: According to KCL, the total current (I) through the circuit can be calculated by adding the individual currents:
$ I = 1 + 1 + 0.5 = 2.5 \, 	ext{A} $
Calculate Total Resistance (R_total)
: The total resistance in the section AB includes the unknown resistance $ X $ and a known resistance of $ 2 \, \Omega $.
$ R_{	ext{total}} = X + 2 \, \Omega $
Power Calculation
: The power absorbed in the section AB is given as $ 50 \, 	ext{W} $. Use the power formula $ P = I^2 R $:
$ 50 = (2.5)^2 (X + 2) $
Solve for X
: Simplify the equation to find the value of $ X $.
$ 50 = 6.25(X + 2) $
$ \Rightarrow X + 2 = 8 $
$ \Rightarrow X = 6 \, \Omega $
Therefore, the value of the resistance $ X $ is $ 6 \, \Omega $.

Answer

$10 \Omega$

Answer

$8 \Omega$

Answer

$6 \Omega$

Answer

$4 \Omega$

Current Electricity

In the following circuit, a power of 50 watt is absorbed in the section AB of the circuit. The value of resistance ' x ' is

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