Question 580: Current Electricity

Question

In potentiometer experiment, cells of e.m.f. '$$E_1$$' and '$$E_2$$' are connected in series $$\left(E_1>E_2\right)$$ the balancing length is $$64 \mathrm{~cm}$$ of the wire. If the polarity of $$E_2$$ is reversed, the balancing length becomes $$32 \mathrm{~cm}$$. The ratio $$\frac{E_1}{E_2}$$ is

Accepted Answer

$$\frac{\mathrm{E}_1}{\mathrm{E}_2}=\frac{\ell_1+\ell_2}{\ell_1+\ell_2}=\frac{64+32}{64-32}=\frac{96}{32}=3$$

Answer

$$1: 1$$

Answer

$$6: 1$$

Answer

$$3: 1$$

Answer

$$2: 1$$

Current Electricity

In potentiometer experiment, cells of e.m.f. '$E_1' and 'E_2' are connected in series \left(E_1>E_2\right) the balancing length is 64 \mathrm{~cm} of the wire. If the polarity of E_2 is reversed, the balancing length becomes 32 \mathrm{~cm}. The ratio \frac{E_1}{E_2}$ is

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