Question 252: Waves

Question

A particle performs S.H.M. of amplitude 'A' and wavelength ' $\lambda$ ', Then the velocity of the wave (V) and the maximum particle velocity (v) are related as

Accepted Answer

A particle performs S.H.M. of amplitude A and wavelength $\lambda$, velocity of wave is V . Maximum particle velocity is given by, $
u=A \omega$
$$ \begin{aligned} &	ext { We know, }\ &\begin{aligned} & \omega=\frac{2 \pi V}{\lambda} \ 	herefore & v=A \cdot \omega=A \cdot \frac{2 \pi V}{\lambda} \ \Rightarrow & v=\frac{2 \pi A}{\lambda} V \end{aligned} \end{aligned} $$

Answer

$v=\frac{\lambda V}{4 \pi A}$

Answer

$\quad V=\frac{\lambda v}{4 \pi A}$

Answer

$\quad v=\frac{2 \pi A}{\lambda} v$

Answer

$V=\frac{2 \pi A}{\lambda} v$

Waves

A particle performs S.H.M. of amplitude 'A' and wavelength ' \lambda ', Then the velocity of the wave (V) and the maximum particle velocity (v) are related as

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