Question 296: Waves

Question

Velocity of sound waves in air is $330 \mathrm{~m} / \mathrm{s}$. For a particular sound wave in air, path difference of 40 cm is equivalent to phase difference of $1.6 \pi$. frequency of this wave is

Accepted Answer

Given: $ \phi = 1.6 \pi $
The wavelength $\lambda$ is given by:
$ \lambda = \frac{V}{f} = \frac{330}{f} \quad 	ext{...(i)} $
We know the relationship for phase difference:
$ \phi = \frac{2 \pi 	imes x}{\lambda} $
where $ x $ is the path difference. Plugging in the values, we have:
$ 1.6 \pi = \frac{2 \pi 	imes (40 	imes 10^{-2}) 	imes f}{330} \quad 	ext{...[From (i)]} $
Solving for $ f $, we find:
$ f = 660 \, 	ext{Hz} $
Thus, the frequency of the wave is $ 660 \, 	ext{Hz} $.

Answer

165 Hz

Answer

150 Hz

Answer

660 Hz

Answer

330 Hz

Waves

Velocity of sound waves in air is 330 \mathrm{~m} / \mathrm{s}. For a particular sound wave in air, path difference of 40 cm is equivalent to phase difference of 1.6 \pi. frequency of this wave is

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