Question 74: Oscillations

Question

A mass $$m$$ is attached to two strings as shown in figure. The spring constants of two springs are $$\mathrm{K}_{1}$$ and $$\mathrm{K}_{2}$$. For the frictionless surface, the time period of oscillation of mass $$m$$ is :

Accepted Answer

Since, both spring are in parallel
Combination, therefore, $K_{	ext {eq }}=K_1+K_2$
Time period of oscillation, $T=2 \pi \sqrt{\frac{m}{K_{	ext {eq }}}} $
$\Rightarrow T=2 \pi \sqrt{\frac{m}{K_1+K_2}}$
Option (a) is correct.

Answer

$$2\pi \sqrt {{m \over {{K_1} + {K_2}}}} $$

Answer

$$2\pi \sqrt {{m \over {{K_1} - {K_2}}}} $$

Answer

$${1 \over {2\pi }}\sqrt {{{{K_1} + {K_2}} \over m}} $$

Answer

$${1 \over {2\pi }}\sqrt {{{{K_1} - {K_2}} \over m}} $$

Oscillations

A mass $m is attached to two strings as shown in figure. The spring constants of two springs are \mathrm{K}_{1} and \mathrm{K}_{2}. For the frictionless surface, the time period of oscillation of mass m$ is :

Choose the correct answer: