Question 78: Oscillations

Question

A particle executes simple harmonic motion between $$x=-A$$ and $$x=+A$$. If time taken by particle to go from $$x=0$$ to $$\frac{A}{2}$$ is 2 s; then time taken by particle in going from $$x=\frac{A}{2}$$ to A is

Accepted Answer

$x=A \sin (\omega t)$
$$
\begin{aligned}
& x=\frac{A}{2}=A \sin (\omega t) \\
& \frac{1}{2}=\sin (\omega t) \\
& t=\left(\frac{\pi}{6 \omega}ight)=2 \\
& \frac{\pi}{\omega}=12 \sec
\end{aligned}
$$
$x=A=A \sin (\omega t)$
$\omega t=\left(\frac{\pi}{2}ight)$
$t=\left(\frac{\pi}{2 \omega}ight)=6$ second
time $=6-2=4$ seconds

Answer

4 s

Answer

1.5 s

Answer

3 s

Answer

2 s

Oscillations

A particle executes simple harmonic motion between $x=-A and x=+A. If time taken by particle to go from x=0 to \frac{A}{2} is 2 s; then time taken by particle in going from x=\frac{A}{2}$ to A is

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