Question 86: Oscillations

Question

The equation of a particle executing simple harmonic motion is given by $$x = \sin \pi \left( {t + {1 \over 3}} \right)m$$. At t = 1s, the speed of particle will be
(Given : $$\pi$$ = 3.14)

Accepted Answer

$$x = \sin \left( {\pi t + {\pi  \over 3}} \right)m$$
$$ \Rightarrow {{dx} \over {dt}} = \pi \cos \left( {\pi t + {\pi  \over 3}} \right)$$
$$ = \pi \cos \left( {\pi  + {\pi  \over 3}} \right)$$ at $$t = 1\,s$$
$$ =  - {\pi  \over 2}$$ m/s
or $$\left| {{{dx} \over {dt}}} \right| = 157$$ cm/s

Answer

0 cm s$$-$$1

Answer

157 cm s$$-$$1

Answer

272 cm s$$-$$1

Answer

314 cm s$$-$$1

Oscillations

The equation of a particle executing simple harmonic motion is given by $x = \sin \pi \left( {t + {1 \over 3}} \right)m. At t = 1s, the speed of particle will be (Given : \pi$ = 3.14)

Choose the correct answer: