Question 71: Oscillations

Question

The variation of kinetic energy (KE) of a particle executing simple harmonic motion with the displacement $$(x)$$ starting from mean position to extreme position (A) is given by

Accepted Answer

For a particle executing SHM
$$
\mathrm{KE}=\frac{1}{2} \mathrm{m} \omega^2\left(\mathrm{A}^2-\mathrm{x}^2\right)
$$
When $\mathrm{x}=0, $ KE is maximum & when $\mathrm{x}=\mathrm{A}, $ KE is zero and KE vs x graph is parabola.

Answer

Answer

Answer

Answer

Oscillations

The variation of kinetic energy (KE) of a particle executing simple harmonic motion with the displacement $(x)$ starting from mean position to extreme position (A) is given by

Choose the correct answer: