Question 80: Oscillations

Question

The time period of oscillation of a simple pendulum of length L suspended from the roof of a vehicle, which moves without friction down an inclined plane of inclination $$\alpha$$, is given by :

Accepted Answer

$$\left| {{g_{eff}}} ight| = \left| {\overline g  - \overline a } ight|$$
$$ \Rightarrow {g_{eff}} = g\cos 	heta $$
$$ \Rightarrow T = 2\pi \sqrt {{l \over {{g_{eff}}}}} $$
$$ = 2\pi  = \sqrt {{L \over {g\cos 	heta }}} $$

Answer

$$2 \pi \sqrt{\mathrm{L} /(\mathrm{g} \cos \alpha)}$$

Answer

$$2 \pi \sqrt{\mathrm{L} /(\mathrm{g} \sin \alpha)}$$

Answer

$$2 \pi \sqrt{\mathrm{L} / \mathrm{g}}$$

Answer

$$2 \pi \sqrt{\mathrm{L} /(\mathrm{g} 	an \alpha)}$$

Oscillations

The time period of oscillation of a simple pendulum of length L suspended from the roof of a vehicle, which moves without friction down an inclined plane of inclination $\alpha$, is given by :

Choose the correct answer: