Question 857: Thermodynamics & KTG

Question

The rate of flow of heat through a metal rod with temperature difference $$40^{\circ} \mathrm{C}$$ is $$1600 \mathrm{~cal} / \mathrm{s}$$. The thermal resistance of metal rod in $${ }^{\circ} \mathrm{C} \mathrm{s} / \mathrm{cal}$$ is

Accepted Answer

Given: rate of flow of heat (conduction rate) $$\mathrm{P}_{	ext {cond }}=1600 \mathrm{~cal} / \mathrm{s}$$
Thermal resistance,
$$\begin{aligned}
& \mathrm{R}_{\mathrm{T}}=\frac{\Delta \mathrm{T}}{\mathrm{P}_{	ext {cond }}} \
& \mathrm{R}_{\mathrm{T}}=\frac{40}{1600} \
& \mathrm{R}_{\mathrm{T}}=0.025^{\circ} \mathrm{Cs} / \mathrm{cal}
\end{aligned}$$

Answer

0.025

Answer

0.25

Answer

2.5

Answer

40

Thermodynamics & KTG

The rate of flow of heat through a metal rod with temperature difference $40^{\circ} \mathrm{C} is 1600 \mathrm{~cal} / \mathrm{s}. The thermal resistance of metal rod in { }^{\circ} \mathrm{C} \mathrm{s} / \mathrm{cal}$ is

Choose the correct answer: