Question 466: Thermodynamics & KTG

Question

In a process, temperature and volume of one mole of an ideal monoatomic gas are varied according to the relation VT = K, where K is a constant. In this process the temperature of the gas is increased by $$\Delta $$T. The
amount of heat absorbed by gas is (R is gas constant) :

Accepted Answer

VT = K
$$ \Rightarrow $$  V$$\left( {{{PV} \over {nR}}} ight)$$ = k $$ \Rightarrow $$ PV
2
= K
$$ \because $$  C = $${R \over {1 - x}} + $$ C
v
(For polytropic process)
C = $${R \over {1 - 2}} + {{3R} \over 2}$$ = $${R \over 2}$$
$$ 	herefore $$  $$\Delta $$Q = nC $$\Delta $$T
= $${R \over 2} 	imes \Delta $$T

Answer

$${1 \over 2}$$ KR$$\Delta $$T

Answer

$${1 \over 2}$$ R$$\Delta $$T

Answer

$${3 \over 2}$$ R$$\Delta $$T

Answer

$${2K \over 3}$$ $$\Delta $$T

Thermodynamics & KTG

In a process, temperature and volume of one mole of an ideal monoatomic gas are varied according to the relation VT = K, where K is a constant. In this process the temperature of the gas is increased by $\Delta $T. The amount of heat absorbed by gas is (R is gas constant) :

Choose the correct answer: