Question 744: Thermodynamics & KTG

Question

What is the pressure of hydrogen in a cylinder of volume 10 litre if its total energy of translation is $7.5 	imes 10^3 \mathrm{~J}$ ?

Accepted Answer

To determine the pressure of hydrogen in a cylinder with a volume of 10 liters, given that its total energy of translation is $7.5 	imes 10^3 \, \mathrm{J}$, we can use the following formula for pressure related to kinetic energy:
$ 	ext{Pressure} = \frac{2}{3} 	imes \frac{	ext{Kinetic Energy}}{	ext{Volume}} $
Plug in the known values:
Kinetic energy = $7.5 	imes 10^3 \, \mathrm{J}$
Volume = $10 \, \mathrm{liters} = 10 	imes 10^{-3} \, \mathrm{m}^3$
$ 	ext{Pressure} = \frac{2 	imes 7.5 	imes 10^3}{3 	imes \left(10 	imes 10^{-3}ight)} = 5 	imes 10^5 \, \mathrm{N/m}^2 $
Therefore, the pressure of hydrogen in the cylinder is $5 	imes 10^5 \, \mathrm{N/m}^2$.

Answer

$5 	imes 10^5 \mathrm{Nm}^{-2}$

Answer

$10^6 \mathrm{Nm}^{-2}$

Answer

$0.5 	imes 10^5 \mathrm{Nm}^{-2}$

Answer

$5 	imes 10^6 \mathrm{Nm}^{-2}$

Thermodynamics & KTG

What is the pressure of hydrogen in a cylinder of volume 10 litre if its total energy of translation is 7.5 \times 10^3 \mathrm{~J} ?

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