Question 864: Thermodynamics & KTG

Question

A metal rod $$2 \mathrm{~m}$$ long increases in length by $$1.6 \mathrm{~mm}$$, when heated from $$0^{\circ} \mathrm{C}$$ to $$60^{\circ} \mathrm{C}$$. The coefficient of linear expansion of metal rod is

Accepted Answer

We know,
Coefficient of Linear expansion $$\alpha=\frac{\mathrm{L}_2-\mathrm{L}_1}{\mathrm{~L}_1 \Delta \mathrm{T}}$$ ...... (i)
Given: $$\Delta \mathrm{T}=60-0=60^{\circ} \mathrm{C}$$
$$\mathrm{L}_1=2 \mathrm{~m}$$ and $$\mathrm{L}_2=2.0016$$
Substituting the given values into (i),
$$\alpha=\frac{.0016}{120}=1.33 	imes 10^{-5} /{ }^{\circ} \mathrm{C}$$

Answer

$$1.33 	imes 10^{-5} /{ }^{\circ} \mathrm{C}$$

Answer

$$1.66 	imes 10^{-5} /{ }^{\circ} \mathrm{C}$$

Answer

$$1.33 	imes 10^{-3} /{ }^{\circ} \mathrm{C}$$

Answer

$$1.66 	imes 10^{-3} /{ }^{\circ} \mathrm{C}$$

Thermodynamics & KTG

A metal rod $2 \mathrm{~m} long increases in length by 1.6 \mathrm{~mm}, when heated from 0^{\circ} \mathrm{C} to 60^{\circ} \mathrm{C}$. The coefficient of linear expansion of metal rod is

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