Question 805: Thermodynamics & KTG

Question

The average translational kinetic energy of nitrogen (molar mass 28) molecules at a particular temperature is 0.042 eV . The translational kinetic energy of oxygen molecules (molar mass 32) in eV at double the temperature is

Accepted Answer

$$\begin{aligned}
&\mathrm{E}_{\left(\mathrm{N}_2ight)}=0.042 \mathrm{eV}\
&	ext { Translational Kinetic Energy is given by, }\
&\begin{array}{ll} 
& \mathrm{E}=\frac{3}{2} \mathrm{kT} \
	herefore & \mathrm{E} \propto \mathrm{~T} \
	herefore & \frac{\mathrm{E}_{\left(\mathrm{N}_2ight)}}{\mathrm{E}_{\left(\mathrm{O}_2ight)}}=\frac{\mathrm{T}_1}{\mathrm{~T}_2} \
	herefore & \frac{0.042}{\mathrm{E}_{\left(\mathrm{O}_2ight)}}=\frac{\mathrm{T}}{2 \mathrm{~T}} \
	herefore & \mathrm{E}_{\left(\mathrm{O}_2ight)}=0.084 \mathrm{eV}
\end{array}
\end{aligned}$$

Answer

0.021

Answer

0.048

Answer

0.056

Answer

0.084

Thermodynamics & KTG

The average translational kinetic energy of nitrogen (molar mass 28) molecules at a particular temperature is 0.042 eV . The translational kinetic energy of oxygen molecules (molar mass 32) in eV at double the temperature is

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