Question 262: Thermodynamics & KTG

Question

A flask contains Hydrogen and Argon in the ratio $2: 1$ by mass. The temperature of the mixture is $30^{\circ} \mathrm{C}$. The ratio of average kinetic energy per molecule of the two gases ( $\mathrm{K}$ argon/K hydrogen) is :

(Given: Atomic Weight of $\mathrm{Ar}=39.9$ )

Accepted Answer

The average kinetic energy per molecule of a gas is given by the expression $\frac{3}{2}kT$, where $k$ is the Boltzmann constant and $T$ is the temperature of the gas in kelvins. Since the temperature of the mixture is given in Celsius, we need to convert it to kelvins by adding 273.15 to get $303.15$ K.
Let us assume that the total mass of the mixture is $3x$ (where $x$ is a constant), then the mass of hydrogen and argon in the mixture will be $2x$ and $x$ respectively, according to the given ratio.
The number of moles of hydrogen and argon can be calculated using their respective masses and molar masses, which are 1 g/mol and 39.9 g/mol respectively. Therefore:
Number of moles of hydrogen = $\frac{2x}{1~\mathrm{g/mol}} = 2x$ mol
Number of moles of argon = $\frac{x}{39.9~\mathrm{g/mol}} = \frac{x}{39.9}$ mol
The total number of moles of gas in the mixture is the sum of the number of moles of hydrogen and argon:
Total number of moles of gas = $2x + \frac{x}{39.9} = \frac{79.9x}{39.9}$ mol
The average kinetic energy per molecule of hydrogen is:
$\frac{3}{2}kT_{\mathrm{H_2}} = \frac{3}{2} 	imes 1.38 	imes 10^{-23} 	imes 303.15~\mathrm{K} = 6.12 	imes 10^{-21}~\mathrm{J}$
The average kinetic energy per molecule of argon is:
$\frac{3}{2}kT_{\mathrm{Ar}} = \frac{3}{2} 	imes 1.38 	imes 10^{-23} 	imes 303.15~\mathrm{K} = 6.12 	imes 10^{-21}~\mathrm{J}$
Therefore, the ratio of the average kinetic energy per molecule of argon to hydrogen is:
$\frac{K_{\mathrm{Ar}}}{K_{\mathrm{H_2}}} = \frac{\frac{3}{2}kT_{\mathrm{Ar}}}{\frac{3}{2}kT_{\mathrm{H_2}}} = \frac{6.12 	imes 10^{-21}~\mathrm{J}}{6.12 	imes 10^{-21}~\mathrm{J}} = 1$
Hence, the ratio of average kinetic energy per molecule of argon to hydrogen is $1$.

Answer

$\frac{39.9}{2}$

Answer

2

Answer

39.9

Answer

1

Thermodynamics & KTG

A flask contains Hydrogen and Argon in the ratio 2: 1 by mass. The temperature of the mixture is 30^{\circ} \mathrm{C}. The ratio of average kinetic energy per molecule of the two gases ( \mathrm{K} argon/K hydrogen) is : (Given: Atomic Weight of \mathrm{Ar}=39.9 )

Choose the correct answer: