Question 421: Thermodynamics & KTG

Question

A heat engine is involved with exchange of heat
of 1915 J, – 40J, + 125 J and –Q J, during one
cycle achieving an efficiency of 50.0%. The
value of Q is

Accepted Answer

$$\eta $$ =
Work done
Heat supplied
$$ \Rightarrow $$ $$\frac{1}{2} $$ = $$\frac{1915-40+125-Q}{1915+125} $$
$$ \Rightarrow $$ $$\frac{1}{2} $$ = $$\frac{2000-Q}{2040} $$
$$ \Rightarrow $$ 2040 = 4000 Ã¢ÂÂ 2Q
$$ \Rightarrow $$ 2Q = 1960
$$ \Rightarrow $$ Q = 980 J

Answer

980 J

Answer

40 J

Answer

400 J

Answer

640 J

Thermodynamics & KTG

A heat engine is involved with exchange of heat of 1915 J, – 40J, + 125 J and –Q J, during one cycle achieving an efficiency of 50.0%. The value of Q is

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