Question 932: Thermodynamics & KTG

Question

Two rods of same length and material are joined end to end. They transfer heat in 8 second. When they are joined in parallel they transfer same amount of heat in same conditions in time

Accepted Answer

Let $$\mathrm{R}$$ be the thermal resistance of each rod when connected in series, the total resistance will be
$$\mathrm{R}_{\mathrm{s}}=2 \mathrm{R}$$
Whey they are connected in parallel, the effective resistance will be
$$\mathrm{R}_{\mathrm{p}}=\frac{\mathrm{R}}{2}
$$
$$	herefore \frac{\mathrm{R}_{\mathrm{p}}}{\mathrm{R}_{\mathrm{s}}}=\frac{1}{4}$$
In parallel combination, the resistance becomes one-fourth and hence time will also become one-fourth. $$\quad 	herefore$$ Time taken $$\frac{8}{4}=2 \mathrm{~s}$$

Answer

3 s

Answer

2 s

Answer

1 s

Answer

4 s

Thermodynamics & KTG

Two rods of same length and material are joined end to end. They transfer heat in 8 second. When they are joined in parallel they transfer same amount of heat in same conditions in time

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