Question 328: Thermodynamics & KTG

Question

The pressure of the gas in a constant volume gas thermometer is 100 cm of mercury when placed in melting ice at 1 atm. When the bulb is placed in a liquid, the pressure becomes 180 cm of mercury. Temperature of the liquid is :
(Given 0$$^\circ$$C = 273 K)

Accepted Answer

Here volume is constant.
$$	herefore$$ $${{{P_1}} \over {{T_1}}} = {{{P_2}} \over {{T_2}}}$$
$$ \Rightarrow {{100} \over {273}} = {{180} \over {{T_2}}}$$
$$ \Rightarrow {T_2} = {{180} \over {100}} 	imes 273$$
$$ = 1.8 	imes 273$$
$$ = 491\,K$$

Answer

300 K

Answer

400 K

Answer

600 K

Answer

491 K

Thermodynamics & KTG

The pressure of the gas in a constant volume gas thermometer is 100 cm of mercury when placed in melting ice at 1 atm. When the bulb is placed in a liquid, the pressure becomes 180 cm of mercury. Temperature of the liquid is : (Given 0$^\circ$C = 273 K)

Choose the correct answer: