Question 825: Thermodynamics & KTG

Question

The efficiency of a heat engine is '$$\eta$$' and the coefficient of performance of a refrigerator is '$$\beta$$'. Then

Accepted Answer

$$\begin{aligned}
\quad \beta & =\frac{T_2}{T_1-T_2} \
\eta & =1-\frac{T_2}{T_1}=\frac{T_1-T_2}{T_1} \
	herefore \quad \eta & =\frac{1}{1+\frac{T_2}{T_1-T_2}} \
	herefore \quad \eta & =\frac{1}{1+\beta}
\end{aligned}$$

Answer

$$\eta=\frac{1}{\beta}$$

Answer

$$\eta=\frac{1}{\beta+1}$$

Answer

$$\eta \beta=\frac{1}{2}$$

Answer

$$\eta=\frac{1}{\beta-1}$$

Thermodynamics & KTG

The efficiency of a heat engine is '$\eta' and the coefficient of performance of a refrigerator is '\beta$'. Then

Choose the correct answer: